If a man`s speed woth and against the wardr current in a river be ` 15 km h^(-1)` and ` 5 km h^(-1)` then tind out the man`s speed in still warer and the speed of the river.

Explanation

If ` v_m , v-w` ar the speeds of man and river water w.r.t. ground. Then ` v=m = v_w = 15 ` and
` v-m - v_w = 5`. On solving , we get,
` v-m = 10 km h^(-1)` and ` v_w = 5 km h^(-1)`.