An object is moving with uniform acceleration. Its velocity after ` 4s is 20 ms^(-1)` and after 7 second is 29 ms"^(-1)` . Find the distanc etravelled by the object in 10 th second.

Explanation

As, ` v= u + at` ltbRgt Fro case (i), ` 20 = u + a xx 4` ..,(i)
for case (ii) ` 29 =u + a xx 7` …(ii)
Solving (i) and (ii) we get
` a= 3 ^(-2), u=8 ms^(-1)`
` S_(10) = u + a/2 92 xx 10 - 1 ] = 8 + 3/ [ 19] = 36.5`.