Two diamonds begin a free fall from rest from the same height, 1.0 s apart. How long after the first diamond begins to fall will the two diamonds be 10 m apart? Take `g = 10 m//s^2.`

Explanation

Let the first body for (t) sec and second body for time ( t-10 second when their separation becomes ` 10 m`. Then
` 10 = 1/2 gt^2 - 1/2 g ( t=12) ^2`
On solving , ` t= 1.5 s`.