The velocity (u)-time (t) graph of an object moving alon a straight line is as shown is Fig. 2 (b) . 30. Calculate the distance covered by object between ` (i) t =0 to t=5 s` (ii) ` t=0 to t=10 s`.
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Explanation

(i) Distance covered by object in timeinterval
` t=0 to t= 5 s= area ` OABD= ( (AB+OD)/2) xx BD`
` = [ (( 5-2)+ 5)/2] xx 20 = 80 m`
(ii) Distance covered by object in time interval ` t=0 to t= 10 s = area OABC`
` = area OABD+ are BCD`
` 80 + 1/2 xx 20 ( 10 - 5) = 130 m`.