The relation between time `t` and distance `x` is `t = ax^(2)+ bx` where `a and `b` are constants. The acceleration is

Explanation

Here, ` t= ax^2 + bx`
Differentiatng both the dises w.r.t. time (t0, we get ` 1=2 ax (dx)/(dt) + b (dx)/(dt) = (2 ax + b) (dx)/(dt)` ltbRgt or ` ( dx)/(dt) = 1/( (2 ax +b))`
velocity , `v = )dx)/(dt) = 1/(( 2 ax+ b)) = ( 2 ax+ b))^1`
Acceleration ` A = (dv)/(dt) = d/(dt) [2 ax + b)^(-1)]`
`=- ( 2 ax+ b)^(-2)xx 2 a (dx)/(dt)`
`= (-2a)/((2 ax+ b)^2 ) xx 1/((2 ax+b))`
`=(-2a)/(( 2 ax+ b))^3`
`=- 2 a v^3` [:. 1/((2 ax+b))=v]`.