If the magnitude of two vectors are ` 3 ` and `6` and ther scalar product is `9`, find the angle between the two vectors.

Explanation

Here, ` A = 3 , B= 6 , vec A. vec B=9`
` cos theta (vec A.vec B)/(AB) = 9/(3 xx 6) = 1/2 = cos 60^2 ` or theta = 60^@`.