A fighter jet plane is flying at a height of ` 500 m` with a velocity ` 450 km h^(-1)` . If release a bob when ` 500 m` away from the enemy post, Will the bomb hit post ? Take g=10 ms^(-2)`.

Explanation

Here, ` y= 500 m`,
u_x = 450 km h^(-1)` = 450 xx 5 ( 18) = 125 ms^(-1)`
Let (t) be the time taken by bomb to reach the ground.
` Taking vertical vertical downward motion of the bomb, we have
` ` u_y =0 , a-y = 10 ms^(-2), y= 500 m, t=?`
y= u_y t + 1/2 a_y t^2`
or ` 500 =0 1/2 xx 10 xx t^2 ` or t= 10 s`
` Horizontal distance coverd by the bobm
` u_x xx t= 125 xx 10 = 1250 m lt 600 m`
Thus the bomb will not hit the enemy post but will fall faar ahead of the target.