A ball is thrown horizontally from the top a tower with a speed of ` 50 ms^(-1)` . Find the velocity and position at the end of ` 3` second. ` g= 9.8 ms^(-2)`.

Explanation

To solve the problem of finding the velocity and position of a ball thrown horizontally from the top of a tower after 3 seconds, we can follow these steps:

### Step 1: Understand the Motion
The ball is thrown horizontally with an initial speed of \( 50 \, \text{m/s} \). The motion can be analyzed in two dimensions: horizontal (x-direction) and vertical (y-direction). The horizontal motion has no acceleration, while the vertical motion is affected by gravity.

### Step 2: Calculate the Vertical Velocity After 3 Seconds
The vertical motion is influenced by gravity, which acts downwards with an acceleration of \( g = 9.8 \, \text{m/s}^2 \). The initial vertical velocity (\( u_y \)) is \( 0 \, \text{m/s} \) since the ball is thrown horizontally.

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