A body is projected downwards at an angle of ` 30^@` to the horizontal with a velocity of `9.8 m//s` from the top of a a tower ` 29 .4m` high. How long will it take before striking the ground ?

Explanation

To solve the problem of a body projected downwards at an angle of \(30^\circ\) to the horizontal with a velocity of \(9.8 \, \text{m/s}\) from the top of a tower \(29.4 \, \text{m}\) high, we can break down the solution into several steps.

### Step 1: Break down the initial velocity into components
The initial velocity \(u\) can be resolved into two components:
- Horizontal component: \(u_x = u \cos(30^\circ)\)
- Vertical component: \(u_y = u \sin(30^\circ)\)

Given \(u = 9.8 \, \text{m/s}\):
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