A body is projected with a velocity ` 30 ms^(-1)` at an angle of `30^@` with the vertical. Find (i) the maximum height (ii) time of flight and (iii) the horizontal range of the projectile. Take ` g=10 m//s^@`.

Explanation

To solve the problem step by step, we will find the maximum height, time of flight, and horizontal range of a projectile projected with a velocity of \(30 \, \text{m/s}\) at an angle of \(30^\circ\) with the vertical. We will take \(g = 10 \, \text{m/s}^2\).

### Step 1: Identify the angle with respect to the horizontal
Since the angle given is with respect to the vertical, we need to convert it to the angle with respect to the horizontal:
\[ \theta = 90^\circ - 30^\circ = 60^\circ \]

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