A ball is thrown from the ground into air. AT a height of ` 9.0 m`, the velcoity is obsecred ot be ` vec v = 7.0 hat i+ 6.0 hat j`. Find the masimum hight to which the ball will rise. ` g= 10 ,s^(-2)`.

Explanation

To solve the problem step by step, we can follow these procedures:

### Step 1: Understand the Given Information
We are given:
- Height at which the velocity is observed, \( h = 9.0 \, \text{m} \)
- Velocity at that height, \( \vec{v} = 7.0 \hat{i} + 6.0 \hat{j} \)
- Acceleration due to gravity, \( g = 10 \, \text{m/s}^2 \)

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