A hammer of mass 1 kg moving with speed of `6 ms^(-1)` strikes a wall and comes to rest in 0.1 s . Calculate (i) the impules of force (ii) the retardation of the hammer , and (iii) the retarding force that stops the hammer .

Explanation

To solve the problem step by step, we will calculate (i) the impulse of force, (ii) the retardation of the hammer, and (iii) the retarding force that stops the hammer.

### Given Data:
- Mass of the hammer (m) = 1 kg
- Initial speed (u) = 6 m/s
- Final speed (v) = 0 m/s (comes to rest)
- Time taken to stop (t) = 0.1 s

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