While leunching a rocket a rocket of mass `2xx 10^(2) kg` , a force of `5 xx 10^(5)` . N is applied for 10 seconds . What is the velocity attained by the rocket at the end of `10 s` ?

Explanation

Here , `m = 2 xx 10^(4) kg , F = 5 xx 10^(5) N, t = 10 s , u = 0 , upsilon = ? `
Impulse of force `F xx t = m = (upsilon - u ) `
` 5 xx 10^(5) xx 10 = 2 xx 10^(4) ( upsilon - 0 ) `
`upsilon = (5 xx 10^(6))/(2xx 10^(4))= 250 m // s` .