A 30 kg Sell is flying at `36 m//s`. When the shell explodes into two parts of `12 kg` and `18 kg` , the lighter part stops, and heavier part files on . What is the velocity of heavier part ? .

Explanation

Here, `M = 30 kg , u = 36 m//s`
`m_(1) = 12 kg , upsilon_(1) = 0 , m_(2) = M- m_(1) = 30 - 12 = 18 kg , upsilon_(2) = ?`
From the law of conservation of lincear momentum ,
`m_(1) upsilon + m_(2) upsilon_(2) = M xx u , 0+ 18 upsilon_(2) = 30 xx 36 upsilon_(2) = (30 xx 36 )/(18)=60 m//s` .