A force acting on a body of mass 2 kg varies with time as shown in fig . 20 find impulse of the force and final velocity of the body.

Explanation

Using Fig . (a) . 20 . Impulse = area under F-t graph
` m (upsilon -u ) = (4xx 2)/(2) + 4 xx 1 + (4xx2)/(2) = 12 N-s `
` 2 (upsilon - 0 )= 12 , upsilon = (12)/(2) =6 ms^(-1) ` .