Find the appared weight of a man weighing 49 kg on earth, when he is standing in a lift which is (i) rising with an acceleration of `1.2 m//s^(2)` (ii) going down with same acceleration (iii) falling freely under gravity (iv) going up or down with unifrom velocity . Take `g= 9.8 m//s^(2) `. \

Explanation

To find the apparent weight of a man weighing 49 kg in different scenarios while standing in a lift, we will use the following formula:

\[ N = M(g \pm a) \]

Where:
- \( N \) is the normal force (apparent weight),
- \( M \) is the mass of the man,
- \( g \) is the acceleration due to gravity (9.8 m/s²),
...