A hunter has a machine gun that can fire 50 g bullets with a velocity of `150 m//s` . A 60 kg tiger springs at him with a velocity of `10 ms^(-1)` How many bullets must the hunter fire per secoud into the tiger in order to stop him in his track.

Explanation

Let n bullets be fired in one second . To stop the tiger in his track rate of change of momentum of bullets = rate of change of momentum of tiger ` n (50xx 10^(-3)) xx 150 = 60 xx 10 `
` n= (60xx 10 )/(50 x 10^(-3) xx 150 )=80 ` .