A man weighing `60kg` runs along the rails with a velocity of `8km//h` and jumps into a car of mass 1 quintal standing on the rails. Calculaate the velocity with which car will start travelling along the rails.

Explanation

Here, `m_(1) = 60 kg` ,
`upsilon_(1) =18 km//h = (18xx 1000)/(60xx 60 ) m//s = 5 m// s`
` m^(2) = 1 "quintal" = 100 kg , upsilon^(2) = 0 , upsilon = ` ? Applying the principal of conservation of linear momentum
`(m_(1)+ m_(2))upsilon= m_(1) upsilon_(1) + m_(2) upsilon_(2) = m_(1) upsilon_(1) `
` upsilon = (m_(1)upsilon_(1))/( m_(1)+ m_(2))=(60+5)/(60+100)=1.88 m//s` .