A car of mass one metric ton travelling at `32m//s`c dashes into the rear of a truck of mass `8000kg` moving in the same direction with a velocity of `4m//s` After the collision the car bounces back wards with a velocity of `8m//s` What is the velocity of the truck after the impact ?

Explanation

Here ,` m_(1) = 1000 kg , u_(1) = 32 m // s , `
` m_(2) = 8000 kg , u_(2) = 4 m//s , upsilon_(1) = - 8 m // s , upsilon = ? `
Using principal of conservation of linear
momentum , ` m_(2) upsilon_(2) + m_(1) = m_(1) u_(1) + m_(2) u_(1) `
` 8000 upsilon_(2) + 1000 xx (-8) = 1000 xx 32 + 8000 xx 4 = 64000 `
` upsilon_(2) = (64000 + 8000)/8000=9 m//s ` .