A hunter has a machine gun that can fire 50 g bullets with a velocity of `150 m//s` . A 60 kg tiger springs at him with a velocity of `10 ms^(-1)` How many bullets must the hunter fire per secoud into the tiger in order to stop him in his track.

Explanation

Here, ` m = 50 g = 50 xx 10^(-3) kg `
` upsilon = 150 m//s , M =60 kg V = 10 m//s `
` n= ` ?
According to the principal of conservation of linear momentum ,
change in momentum of bullets = change in momentum of tiger
` nxx m xx upsilon = MV `
` n = (MV)/(mxxupsilon )=(60xx10)/(50 xx 10^(-3) xx 150 `
` n = 80` (bullet/sec).