A rocket motor consumes 100 kg of fuel per second exhausting it with a speed of `6 xx 10^(3) ms^(-1)` What thrust is exerted on the rocket ? What will be the velocity of the rocket at the instant its mass is reduced to `(1 // 40)` of its initial mass ? Take initial velocity of rocket as zero . Neglect gravity .

Explanation

Here ` (dm)/(dt) = 100 kg wt//s `
`u = 6 10^(3) m//s`
Thrust `F = u (dm)/(dt) = 6 xx 10^(3) xx 100 `
`= 6 xx 10^(5) N`
(ii) `upsilon = ? ,m = (1)/(40) m_(0)`
`(m_(0))/(m) = 40`
`upsilon = (2.303) u log_(10) (m_(0)/(m))`
`2.303 xx 6xx 10^(3) xx log_(10) 40`
` = 2 .303 xx 6xx 10^(3) xx 1.602`
`22.13 xx 10^(3) m//s` .