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A train is moving along a horizontal tra...

A train is moving along a horizontal track . A pendulum suspended from the roof makes an angle of `4^(@)` with the vertical . If `g = 10 m//s^(2)` , what is the acceleration of the train ?

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` T cos 4^(@) = mg and T sin 4^(@) = ma `
Dividing . We get ` (Tsin 4 ^(@))/(T cos 4^(@))=(ma)/(mg)=(a)/(g) `
` a = g tan 4^(@) = 10 xx 0.07 = 0.7 m//s^(2) `
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