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A mass of 6 kg is suspended by a rope of...

A mass of 6 kg is suspended by a rope of length 2 m from the ceilling A force of 50 N in the horizontal direction is applied at the mid - point P of the rope as shown . What is the angle the rope makes with the vertical in equilibrium ? (Take = `10 ms^(-2)`) . Neglect mass of the rope .

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To solve the problem of finding the angle the rope makes with the vertical in equilibrium when a horizontal force is applied, we can follow these steps: ### Step 1: Identify the forces acting on the mass The forces acting on the mass are: 1. The weight of the mass (W) acting downwards, which is given by: \[ W = mg \] ...
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A mass of 20 kg is suspended by a rope of length 2 m from a ceiling. A force of 173.2 N in the horizontal direction is applied at the midpoint of the rope as shown in Fig. What is the angle the rope makes with the horizontal in equilibrium ? Take g = 10 ms^(-2) . Neglect mass of the rope.

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A block fof mass 5kg is suspended by a massless rope of length 2 m from the ceilling. A force of 50 N is applied in the horizontal direction at the midpoint P of the rope, as shown in the figure. The angle made by the rope with the vertical in equilibrium is (Take g=10ms^(-2)m .

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A mass of 10 kg is suspended vertically by a rope of length 2 m from a ceiling. A force of 60 N is applied at the middle point of the rope in the horizontal direction, as shown in Fig. Calculate the angle the rope makes with the vertical. Neglect the mass of the rope and take g =10ms^(-2) .

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