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A mass of 6 kg is suspended by a rope of...

A mass of 6 kg is suspended by a rope of length 2 m from the ceilling A force of 50 N in the horizontal direction is applied at the mid - point P of the rope as shown . What is the angle the rope makes with the vertical in equilibrium ? (Take = `10 ms^(-2)`) . Neglect mass of the rope .

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To solve the problem of finding the angle the rope makes with the vertical in equilibrium when a horizontal force is applied, we can follow these steps: ### Step 1: Identify the forces acting on the mass The forces acting on the mass are: 1. The weight of the mass (W) acting downwards, which is given by: \[ W = mg \] ...
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Knowledge Check

  • A mass of 4kg is suspended by a rope of length 4m from a ceiling. A force of 20N in the horizontal direction is applied at the mid-point of the rope as shown in figure. What is the angle which the rope makes with the vertical in equilibrium? Neglect the mass of the rope. Take g=10ms^(-2) .

    A
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    B
    `tan^(-1)((1)/(2))`
    C
    `tan^(-1)sqrt(2)`
    D
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  • A mass of 6 kg is suspended by a rope of length 2m from a celling. A force of 50N is applied in horizontal direction at the mid point of the rope. What is the angle of the rope with the verticle in equilibrium:-

    A
    `tan^(-1)((4)/(5))`
    B
    `tan^(-1)((5)/(4))`
    C
    `tan^(-1)((5)/(6))`
    D
    None of these

  • A block fof mass 5kg is suspended by a massless rope of length 2 m from the ceilling. A force of 50 N is applied in the horizontal direction at the midpoint P of the rope, as shown in the figure. The angle made by the rope with the vertical in equilibrium is (Take g=10ms^(-2)m .

    A
    `30^(@)`
    B
    `40^(@)`
    C
    `60^(@)`
    D
    `45^(@)`

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