A block of mass 100 kg is set into motion on a frictionless horizontal surface with the help of a frictionless pulley and rope system shown in What horizontal force should be applied on the rope to produce an acceleration of `0.1 m//s^(2)`
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Explanation

Here , m = 100 kg If is force applied on the free end ogf the rope , then as is clear from
` F + F = T = ma `
` F = (ma)/(2) = (100xx0.1)/(2)= 5N ` .