Two blocks of masses 50 kg and 30 kg connected by a massless string pass over a light frictionless pulley and rest on two smooth planes inclined at angles `30^(@)` and `60^(@)` resp . With horizontal .Determine the accelertion in the two blocks and tension in the string `g = 10 m//s^(2)` .

Explanation

To solve the problem, we will analyze the forces acting on each block and apply Newton's second law. Here are the steps to find the acceleration of the blocks and the tension in the string.

### Step 1: Identify the forces acting on each block

1. **For Block 1 (mass = 30 kg, inclined at 60°)**:
- Weight (mg) acting downward: \( W_1 = 30 \times g = 30 \times 10 = 300 \, \text{N} \)
- The component of weight acting down the incline: \( W_{1x} = W_1 \sin(60°) = 300 \sin(60°) = 300 \times \frac{\sqrt{3}}{2} = 150\sqrt{3} \, \text{N} \)
- Tension (T) acting up the incline.
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