A cricket ball is rolled on ice with a velocity of `5.6 m//s` and comes to rest after travelling 8 m . Find the coefficient of friction Given `g = 9.8 m//s^(2)` .

Explanation

Here , ` u = 5.6 m//s , upsilon = 0 , s = 8 m , g = 9.8 m//s^(2) `
From ` upsilon^(2) - u^(2) = 2 a s `
` 0 - (5.6)^(2) = 2 xx a xx 8 `
`:. a = (5.6 xx 5.6)/(16 )=- 1.96 m//s^(2) `
` mu_(k) = (a)/(g) = (1.96)/(9.8)=0 .2 ` .