The coefficient of friction between the ground and the wheels of a car between the ground and the wheels of acar moving on a horizontal road is 0.5 If the car starts from rest , what is the minimum distance in which it can acquire a speed of `72 km // h` ? take `g = 10 ms^(-2)` .

Explanation

To solve the problem, we need to find the minimum distance a car can travel to reach a speed of 72 km/h, given that the coefficient of friction between the car's wheels and the ground is 0.5 and that the acceleration due to gravity (g) is 10 m/s².

### Step-by-Step Solution:

1. **Convert the speed from km/h to m/s**:
\[ \text{Speed} = 72 \text{ km/h} = 72 \times \frac{5}{18} = 20 \text{ m/s} \]
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