A cubical block rests on an inclined plance of `mu = (1)/sqrt(3)` . Determine the angle at which the block just slides down the incline .

Explanation

To determine the angle at which a cubical block just starts to slide down an inclined plane with a coefficient of friction \( \mu = \frac{1}{\sqrt{3}} \), we can follow these steps:

### Step 1: Understand the Forces Acting on the Block
When the block is on the inclined plane, the forces acting on it are:
- The gravitational force \( \vec{W} = mg \) acting downwards.
- The normal force \( \vec{N} \) acting perpendicular to the surface of the incline.
- The frictional force \( \vec{F_f} \) acting up the incline, opposing the motion.

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