A block of mass 10 kg is sliding on a surface inclined at `30^(@)` with horizontal . If coefficient of friction between the block and the surface is 0.5 , find acceleration produced in the block . Take ` g = 9.8 m //^(2)` .

Explanation

To find the acceleration produced in the block sliding down an inclined plane, we can follow these steps:

### Step 1: Identify the forces acting on the block
- The gravitational force acting downward: \( F_g = mg \)
- The component of gravitational force acting parallel to the incline: \( F_{\parallel} = mg \sin(\theta) \)
- The component of gravitational force acting perpendicular to the incline: \( F_{\perpendicular} = mg \cos(\theta) \)
- The normal force \( N \) acting perpendicular to the incline
- The frictional force \( F_f \) acting opposite to the direction of motion: \( F_f = \mu N \)
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