Find the force required to move a train of 2000 quintals up an incline of 1 in 50 , with an acceleration of `2 ms^(-2)`, the force of friction being 0.5 newton per quintal.

Explanation

Here , `m = 2000 "quintals"`
`= 2000 xx 100 kg`
`sin 0 = (1)/(50) , a = 2 ms^(-2)`
force of friction ` = 0.5 ` per quintal
`F = 0.5 xx 2000 = 1000 N`
In moving up inclined plance , force required against gravity
`= mg sin 0 = 200 , 000 xx 9.8 xx (1)/(50)`
`= 39200 N`
Also , force required to produce acceleration
` = ma = 200 , 000 xx 2 = 400 , 000 N `
`:.` Total force required `= 1000 + 39 , 200 + 400 , 000 `
` 440 , 200 N ` .