A block of mental of mass 50 gram placed over an inclined plane at an angle of `15^(@)` slides down without acceleration . If the inclination is increased by `15^(@)` , what would be the acceleration of the block ?

Explanation

Here , ` m = 50 g = 0 .05 kg `
Angle of repose , ` alpha = 15^(@) , theta = 15^(@) = 30^(@) , `
` a = ? `
` mu = tan alpha = tan 15^(@) = 0.2679 `
Net downward force on the block , down the incline ,
`F = mg sin theta - f `
` ma = mg sin theta - mu mg cos theta `
` :. a = g (sin theta - mu cos theta) `
` = 9.8 (sin 30^(@) - mu cos 30^(@)) `
` = 9.8 (0.5 - 0. 2679 xx sqrt(3//2)) `
` a = 2 .6 m // s ^2` .