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A string breaks under a load of 4.8kg A ...

A string breaks under a load of 4.8kg A mass of 0.5 kg is attached to one end of a string 2 m long and is rotated in a horizontal circle. Calculate the greatest number of revolutions that the mass can make without breaking the string.

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To solve the problem step by step, we will follow the physics concepts involved in circular motion and tension in the string. ### Step 1: Determine the maximum tension in the string. The string breaks under a load of 4.8 kg. To find the maximum tension (T_max) in Newtons, we use the formula: \[ T_{\text{max}} = m \cdot g \] where: - \( m = 4.8 \, \text{kg} \) (the mass that breaks the string) - \( g = 9.8 \, \text{m/s}^2 \) (acceleration due to gravity) ...
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