A particle describes a horizontal circle on the smooth inner surface of a conical funnel as shown in Fig. If the height of the plane of the circle above the vertex is `9.8 cm`, find the speed of the particle.

Explanation

Here , ` h = 9.8 cm , upsilon ? `
As is clear from
`R cos alpha = (m upsilon)^(2)/(r)`
`R sin alpha = mg`
Dividing , we get , `tan alpha = (rg)/(upsilon^(2))` or `(r)/(h)=(rg)/(upsilon^(2)`
`upsilon sqrt(gh)= sqrt(9.8 xx (9.8)/(100)) = 0.98 m// s ` .