A block of mass 1 kg lies on a horizontal surface in a truck. The coefficient of static friction between the block and the surface is 0.6. If the acceleration of the truck is `5m//s^2`, the frictional force acting on the block is…………newtons.

Explanation

Limiting force of friction
` F = mu R = mu mg = 0.6 xx 1 xx 9.8 = 5 .88 N `
Applied force , ` F = ma = 1 xx 5 = 5 N `
As F lt F , the block would not move . Force of friction = applied force = 5 N .