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A bucket of water is rotated in a vertic...

A bucket of water is rotated in a vertical circle so that surface of water is at a distance r from the axix of rotation What is the minimum angular velocity so that the water does not spill out ?

A

`sqrt(2g//r)` .

B

`sqrt(g//r)` .

C

`sqrt(3g//r)` .

D

`sqrt(4g//r)` .

Text Solution

Verified by Experts

The correct Answer is:
B
For water not to spill weight of water must be balanced by centrifugal force (`m r omega^(2)` )
i.e `m r omega^(2) = mg , omega= sqrt(g//r)` .
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