A ball rolling on ice with a velocity of `4 .9 m//s` stops after travelling 4 m . If `g = 9.8 m//s^(2)` what is the coefficient of friction ?

Explanation

Here , ` u = 4.9 m//s , upsilon = 0 , s = 4 m `
` g = 9.8 m//s^(2) , mu = ` ?
` upsilon^(2) - u^(2) = 2 as = 2 (-mu g ) s `
` mu= (upsilon^(2) - u^(2))/(-2gs) = (0-(4.9)^(2))/(-2 xx 9.8 xx 4 )= 0.31 ` .