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A stone of mass 0.2 kg is tied to one en...

A stone of mass `0.2` kg is tied to one end of a string of length ` 80cm` Holding the other end, the stone is wirled into a vertical circle. What is the minimum speed of the stone at the lowest point so that it just completes the circle What is the tension in the string at the lowest point of the circular path ? . `(g =10^(-2)) ` .

Text Solution

Verified by Experts

Here, ` m = 0.2 kg, l = r = 80 cm = 0.8, upsilon_(L) =? T_(L) = ?`
`upsilon_(L) = sqrt(5g r) = sqrt(5xx10xx0.8)= 6.32 ms^(-1), T_(L) = 6 mg = 6xx 0.2 xx 10 = 12 N ` .
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Knowledge Check

  • A stone of mass 0.2 kg is tied to one end of a string of length 80 cm. Holding the other and, the stone is whiled into a vertical circle. The minimum speed of the stone and tension at the lowest point of circular path so that it just comletes the circle are

    A
    `5ms^(-1),10N`
    B
    `6.32ms^(-1),12N`
    C
    `6.32ms^(-1),10N`
    D
    `2ms^(-1),10N`

  • IF a stone is tied to one end of the string and whirled in verticle circle, then the tension in the string at the lowest point is equal to

    A
    centripetal force
    B
    the difference between centripetal force and weight of the stone
    C
    the addition of the centripetal force and weight of the stone
    D
    weight of the stone

  • A small stone of mass 50 g is rotated in a vertical circle of radius 40 cm. What is the minimum tension in the string at the lowest point?

    A
    `6`N
    B
    `2`N
    C
    `3`N
    D
    `1.5`N

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