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A particle of mass 20 g is whirled into ...

A particle of mass 20 g is whirled into a vertical circle of radius 80cm using a massless string The speed of the particle when the string makes an angle `60^(@)` with the verticle line is `1.5ms^(-1)` What is the tension in the string in this position ?

Text Solution

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Here, ` m =200 g = 0.2 kg, r = 80 cm = 0.8 m, upsilon = 1.5 m//s, theta = 60^(@) , T = ?`
From ` T = (m upsilon^(2))/(r) + cos theta = (0.2 xx 1.5 xx 1.5)/(0.8) + 0.2 xx 10 cos 60^(@) = 0.56 + 1 = 1.56 N` .
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