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A person of mass 50 kg stands on a weigh...

A person of mass 50 kg stands on a weighing scale on a lift . If the lift is descending with a downward acceleration of `9ms^(-2)` what would be the reading of the weighing scale? `(g =10ms^(-2)) ` .

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To solve the problem, we need to determine the reading on the weighing scale when a person of mass 50 kg is standing on it in a lift that is descending with an acceleration of \(9 \, \text{m/s}^2\). We will use Newton's second law of motion to find the normal force acting on the person, which is what the weighing scale measures. ### Step-by-Step Solution: 1. **Identify the Forces Acting on the Person**: - The gravitational force acting on the person (weight) is given by: \[ F_g = m \cdot g ...
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