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The velocity of a body of mass 2 kg as...

The velocity of a body of mass ` 2 kg ` as a function of t is given by ` upsilon(t) = 2t hati + t^(2) hatj ` Find the momentum and force acting on it at time `t = 2 s`.

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Here, ` m = 2kg `
`upsilon(t) = 2t hati + 2^(2) hatj `
` t = 2 s `
` vec(upsilon) = 4 hati + 4hatj = 4(hati + hatj) `
`:. vec(p) = vec (m upsilon) =2 (4hati + 4hatj) = [8hati + 8hatj] kgms^(-1)`
Also, `vec(a)=(d vec (v))/(dt)=(d)/(dt)[a t hat(i) +t^(2)hat (j)]`
`vec(a) = 2 hati + 2t hatj `
At `t =2 s, vec(a) 2hati + 4hati `
` vec(F) = m vec(a) = 2 (2hati + 4hatj) = (4hati + 8hati) N`.
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