Figure shows `(v_x`,t) and `(v_y`,t) diagram for a body of unit mass. Find the force as a function of time.

Explanation

As is clear from
`{:(v_(x)=2t",","for",0 lt t lt 1s,|,v_(y)=t,"for",0 lt t lt 1s),(v_(x)=2(2-t)",","for",1 lt t lt 2s,v_(y)=1,"for",0 lt t,),(v_(x)=2(2-t)",","for",2 lt t,,,,):}`
` :. F_(x) = ma_(x) = m(d upsilon_(x))/(dt)" "F_(y) = ma _(y) = m(dupsilon_(y))/(dt)`
`{:(=1 xx 2,"for",0 lt t lt1 s,|,=1 xx 1,"for",0 lt t lt 1s),(=1(-2),"for",1 lt tlt 2s,=0,"for",1 lt t,),(=0,"for",2 lt t,,,,):}`
Hence `vec(F) = - 2 hati + hatj` for `0 lt t lt 1 s `
`vecF = - 2 hati` for `1 lt t lt2 s`
`vec(F) = vec(0)` for `2 lt t `
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