A ship of mass `3xx10^7kg` initially at rest, is pulled by a force of `5xx10^5N` through a distance of 3m. Assuming that the resistance due to water is negligible, the speed of the ship is

Answer

`0.1 ms^(-1)`

Explanation

Here, `m=3 xx 10^(7)kg, u=0, s=3m`
`F =5 xx 10^(4) N, upsilon = ?`
As `a = F//m = (5 xx 10^(4))/(3 xx 10^(7)) = (5)/(3) xx10^(-3) m//s^(2)`
From `v^(2) - u^(2) = 2 as `
`v^(2) - 0 = 2 xx (5)/(3) xx 10^(-3) xx3 =10^(-2)`
`v= 10^(-1) ms^(-1) = 0.1 ms^(-1)` .