In an `X-ray` machine an electron is subjected to a force of `10^(23) N` In how much time will the electron a distance of `0.1m` ? Take mass of electron `=10^(-30)kg` .

Answer

`1.4 xx10^(4)s`

Explanation

Here, `F =10^(-23) N, t = ?, s =0.1 m`
`m = 10^(-30)kg, u=0`
`a = (F)/(m) =10^(-23)/(10^(-30)) = 10^(7) m//s^(2)`
From `s = ut + (1)/(2)at^(2)`
`0.1 = 0 + (1)/(2) xx 10^(7) t^(2) , t^(2) = (0.2)/(10^(7)) = 2xx 10^(-8)`
`:. T =sqrt2 xx 10^(-4) s = 1.4 xx 10^(-4) s`.