A bullet of mass `50g` moving with a speed of `500 ms^(-1)` is brought to rest in `0.01s` Find the impulse and the average force .

Answer

`-25 N_s, - 2500 N` .

Explanation

Here, `m = 50 g = 0.05 kg, u =500 m//s`
`upsilon = 0, t = 0.01 s`
Impulse = change in momentum
`m (upsilon - m) = 0.05 (0-500)= - 25 Ns`
As Impulse ` = Fxxt`
`:. - 25 = F xx 0.01, F = -(25)/(0.01) = - 2500 N` .