An elevator starts from rest with a constant downward acceleration and covers `2.5m` in first second If the lift weighs `200kg` what would be the tension in the ropes of the lift ?

Answer

`960N` .

Explanation

Here, `u =0, s = 2.5 m, t = 1 s, m t =1 s, m =200 kg`
`R=`?
`s = ut + (1)/(2) at^(2) = (1)/(2)at^(2)`
`a = (2s)/(t^(2)) =(2xx2.5)/(1^(2)) =5 m//s^(2)`
`R =m (g -a) = 200 (9.8 -5)`
`=960N` .