A body of mass `50kg` is put on a spring weighing machine in a lift What is the reading of the machine when (i) Lift ascends with a unifrom velocity of `10m//s` (ii)descends with an acceleration of `5m//s^(2)` ? Take `of = 10m//s^(2)` .

Answer

`50kg f; 25kg f` .

Explanation

Here, `m = 50 kg. R_(1) = ? upsilon = 10 m//s a_(1) = 0`
`R_(2) = ? A_(2) = 5 m//s^(2) g =10 m//s^(2)`
`R_(1) = m (g +a_(1)) = 50 (10 + 0) = 500 N = 50 kg f`
`R_(2) = m (g - a_(2)) = 50 (10 -5) = 250 N = 25 kg f` .