A ball of mass `1kg` hangs in equilibrium from two strings as shown in If `g = 10m//s^(2)` what are the valuse of tension in strings `OA` and `OB`
.

Answer

`5 N ; 5sqrt3N` .

Explanation

As shown in the three force `T_(1), T_(2)`
and mg acting at`O` are in equilibrium Applying
Lami s theorem we get
`(T_(1))/(sin 150^(@)) =(T_(2))/(sin 120^(@)) = (mg)/(sin90^@)`
`T_(1) = (mg)/(sin 90^(@)) xxsin 150^(@) = (10 sin 30^(@))/(1) = 5 N`
`T_(2) = (mg)/(sin90^(@)) xxsin120^(@) = (10sqrt3//2)/(1) = 5 sqrt3N` .