An automobile is moving on a horizontal road with a speed `upsilon` If the coefficient of friction between the tyres and the road is `mu` show that the shortest distance in which the automobile can be stooped is `upsilon^(2)//2 mu g`.

Explanation

Here, `u = upsilon, a = - mu g , s = ? upsilon = 0`
From `upsilon^(2) - u^(2) = 2 as`
`0 - upsilon^(2) = 2 (-mu g) s , s =upsilon^(2)//2 mu g` .