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Calculate the power of an engine which can pull a train of mass `25000` quintal up an incline of 1 in 100 at the rate of `10.8km//h` Resistance due to friction is `2N//"guintal"`.

Text Solution

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The correct Answer is:
`8.85 xx 10^(5) watt`
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Calculate the power of an engine , which can just pull a train of mass 5000 quintals up an incline of 1 in 50 at the rate of 54 km//h . The resistance due to friction is 0.8 N //"quintal" . Take g = 9.8 m//s^(2) .

Find the power of an engine which can draw a train of 400 metric ton up the inclined plane of 1 in 98 at the rate 10 ms^(-1) . The resistance due to friction acting on the train is 10 N per ton.

Knowledge Check

  • What is the power of an engine required to move a train of mass 400 metric tons with a speed of 36 km/h, on a level track, if the force of friction is 10 N/metric ton?

    A
    20 kW
    B
    30 kW
    C
    40 kW
    D
    50 kW

  • The work done in dragging a stone of mass 100 kg up an inclined plane 1 in 100 through a distance of 10 m is ("takeg" = 9.8 m//s^(2))

    A
    zero
    B
    `980 J`
    C
    `9800 J`
    D
    `98 J`

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