A cyclist goes round a circular track of `440` metres length in `20` seconds Find the angle that his cycle makes with the verticle.

Answer

`35^(@) 12` .

Explanation

Let r be radius of the track
`2pi r = 440 m`
`r = (440)/(2pi) m, upsilon = (2pi r)/(t) = (440)/(20) = 22ms^(-1)`
As `tan theta = (upsilon^(2))/(rg)`
`:. Tan theta =(22xx22xx2pi)/(440 xx 9.8) = 0.7055`
`theta = 35^(@) 12` .